编程求三个数字x、y、z (其范围均为0~9) 组成的两个三位整数,且满足: xyz+zyx=1231。C语言编程?

2025-12-17 00:22:56
推荐回答(1个)
回答1:

#include
main()
{
int x,y,z;
for(x=1;x<=9;x++)
for(y=0;y<=9;y++)
for(z=1;z<=9;z++)
if(100*x+10*y+z+100*z+10*y+x == 1231)
printf("x=%d,y=%d,z=%d\n",x,y,z);
}