lncos3x÷lncos4x趋向于0的极限,快快,,,考试那

2025-12-17 11:57:37
推荐回答(2个)
回答1:

lim lncos3x÷lncos4x
=lim (-3sin3x/cos3x)÷(-4sin4x/cos4x)
=lim (3sin3x)/(4sin4x)
=lim (9cos3x)/(16cos4x)
=9/16

回答2:

lim(x→0)lncos3x÷lncos4x
=lim(x→0)(-3sin3x/cos3x)/(-4sin4x/cos4x)
=lim(x→0)(3sin3x)/(4sin4x)
=lim(x→0)(9cos3x)/(16cos4x)
=9/16