直线是y=3x/2+m代入9x²+4y²=3618x²+12mx+4m²-36=0x1+x2=-12m/18=-2m/3y=3x/2+m所以y1+y2=3x1/2+m+3x2/2+m=3/2(x1+x2)+2m=-m+2m=m中点则x=(x1+x2)/2,y=(y1+y2)/2即x=-m/3y=m/2所以y/x=-3/2y=-3x/2所以在一条直线上
