【高中数学】如题,PA,PB,PC是怎么算出的?

2025-05-07 23:05:38
推荐回答(1个)
回答1:

P(AC)/P(AB)=2
[P(A)P(C)]/[P(A)P(B)]=2
P(C)/P(B)=2
P(B)=0.5P(C)
带入P(BC)=P(B)P(C)=0.5P²(C)=0.125
P(C)=0.5 P(B)=0.25 P(A)=0.2